Practicing Coding Interview Questions in Python
Kirill Smirnov
Data Science Consultant, Altran
map( )
map( Iterable1, Iterable2, ...)
Iterables: [1, 2, 3, 4, 5]
, [10, 20, 30, 40, 50]
, ...
map(function(x1, x2, ...), Iterable1, Iterable2, ...)
Iterables: [1, 2, 3, 4, 5]
, [10, 20, 30, 40, 50]
, ...
1
, 10
, ... $\rightarrow$ function(1, 10, ...)
$\rightarrow$ new object
2
, 20
, ... $\rightarrow$ function(2, 20, ...)
$\rightarrow$ new object
3
, 30
, ... $\rightarrow$ function(3, 30, ...)
$\rightarrow$ new object
4
, 40
, ... $\rightarrow$ function(4, 40, ...)
$\rightarrow$ new object
5
, 50
, ... $\rightarrow$ function(5, 50, ...)
$\rightarrow$ new object
nums = [1, 2, 3, 4, 5]
The task is to get [1, 4, 9, 16, 25]
def squared(x):
return x**2
squares = map(squared, nums)
print(squares)
<map object at 0x7fdbe4ab3da0>
squares
is iterable
for square in squares:
print(square)
1
4
9
16
25
nums = [1, 2, 3, 4, 5]
The task is to get [1, 4, 9, 16, 25]
def squared(x):
return x**2
squares = map(squared, nums)
print(squares)
<map object at 0x7fdbe4ab3da0>
squares
is Iterable
list(squares)
[1, 4, 9, 16, 25]
nums = [1, 2, 3, 4, 5]
The task is to get [1, 4, 9, 16, 25]
def squared(x):
return x**2
squares = map(squared, nums)
print(squares)
<map object at 0x7fdbe4ab3da0>
squares
is Iterator
next(squares)
1
next(squares)
4
nums = [1, 2, 3, 4, 5]
The task is to get [1, 4, 9, 16, 25]
def squared(x):
return x**2
squares = map(squared, nums)
list(squares)
[1, 4, 9, 16, 25]
nums = [1, 2, 3, 4, 5]
The task is to get [1, 4, 9, 16, 25]
squares = map(lambda x: x**2, nums)
list(squares)
[1, 4, 9, 16, 25]
nums1 = [1, 2, 3, 4, 5]
nums2 = [10, 20, 30, 40, 50]
The task is to get: [1*10, 2*20, 3*30, 4*40, 5*50] = [10, 40, 90, 160, 250]
mult = map(lambda x, y: x*y, nums1, nums2)
list(mult)
[10, 40, 90, 160, 250]
filter( )
filter( Iterable)
Iterable: [1, 2, 3, 4, 5]
filter(function(x), Iterable)
Iterable: [1, 2, 3, 4, 5]
1
$\rightarrow$ function(1)
$\rightarrow$ True
$\rightarrow$ 1
is kept
2
$\rightarrow$ function(2)
$\rightarrow$ False
$\rightarrow$ 2
is rejected
3
$\rightarrow$ function(3)
$\rightarrow$ True
$\rightarrow$ 3
is kept
4
$\rightarrow$ function(4)
$\rightarrow$ False
$\rightarrow$ 4
is rejected
5
$\rightarrow$ function(5)
$\rightarrow$ True
$\rightarrow$ 5
is kept
nums = [-3, -2, -1, 0, 1, 2, 3]
The task is to get: [1, 2, 3]
def positive(x):
return x > 0
fobj = filter(positive, nums)
print(fobj)
<filter object at 0x7f196d378d68>
fobj
is Iterable
for item in fobj:
print(item)
1
2
3
nums = [-3, -2, -1, 0, 1, 2, 3]
The task is to get: [1, 2, 3]
def positive(x):
return x > 0
fobj = filter(positive, nums)
print(fobj)
<filter object at 0x7f196d378d68>
fobj
is Iterable
list(fobj)
[1, 2, 3]
nums = [-3, -2, -1, 0, 1, 2, 3]
The task is to get: [1, 2, 3]
def positive(x):
return x > 0
fobj = filter(positive, nums)
print(fobj)
<filter object at 0x7f196d378d68>
fobj
is Iterator
next(fobj)
1
next(fobj)
4
nums = [-3, -2, -1, 0, 1, 2, 3]
The task is to get: [1, 2, 3]
def positive(x):
return x > 0
fobj = filter(positive, nums)
list(fobj)
[1, 2, 3]
nums = [-3, -2, -1, 0, 1, 2, 3]
The task is to get: [1, 2, 3]
fobj = filter(lambda x: x > 0, nums)
list(fobj)
[1, 2, 3]
from functools import reduce
reduce(function(x, y), Iterable)
Iterable: [1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
$\rightarrow$ new object of the same type as the content
from functools import reduce
reduce(function(x, y), Iterable)
Iterable: [1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
$\rightarrow$ new object of the same type as the content
from functools import reduce
reduce(function(x, y), Iterable)
Iterable: [1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
$\rightarrow$ new object of the same type as the content
from functools import reduce
reduce(function(x, y), Iterable)
Iterable: [1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
$\rightarrow$ new object of the same type as the content
from functools import reduce
reduce(function(x, y), Iterable)
Iterable: [1, 2, 3, 4, 5]
[1, 2, 3, 4, 5]
$\rightarrow$ new object of the same type as the content
nums = [8, 4, 5, 1, 9]
The task is to get: 1
- minimum
def smallest(x, y):
if x < y:
return x
else:
return y
reduce(smallest, nums)
1
smallest(8, 4)
$\rightarrow$ 4
smallest(4, 5)
$\rightarrow$ 4
smallest(4, 1)
$\rightarrow$ 1
smallest(1, 9)
$\rightarrow$ 1
- final result
nums = [8, 1, 4, 2, 9]
The task is to get: 1
- minimum
def smallest(x, y):
if x < y:
return x
else:
return y
reduce(smallest, nums)
1
nums = [8, 1, 4, 2, 9]
The task is to get: 1
- minimum
reduce(lambda x, y: x if x < y else y, nums)
1
Practicing Coding Interview Questions in Python