Toma de decisiones basada en datos en SQL
Irene Ortner
Data Scientist at Applied Statistics
Nuestra pregunta ¿Quién es el actor favorito de un determinado grupo de clientes?
Une la tabla renting con las tablas
customersactsinactorsSELECT *
FROM renting as r
LEFT JOIN customers AS c
ON r.customer_id = c.customer_id
LEFT JOIN actsin as ai
ON r.movie_id = ai.movie_id
LEFT JOIN actors as a
ON ai.actor_id = a.actor_id;
SELECT a.name,
COUNT(*)
FROM renting as r
LEFT JOIN customers AS c
ON r.customer_id = c.customer_id
LEFT JOIN actsin as ai
ON r.movie_id = ai.movie_id
LEFT JOIN actors as a
ON ai.actor_id = a.actor_id
WHERE c.gender = 'male'
GROUP BY a.name;
SELECT a.name,
COUNT(*) AS number_views,
AVG(r.rating) AS avg_rating
FROM renting as r
LEFT JOIN customers AS c
ON r.customer_id = c.customer_id
LEFT JOIN actsin as ai
ON r.movie_id = ai.movie_id
LEFT JOIN actors as a
ON ai.actor_id = a.actor_id
WHERE c.gender = 'male'
GROUP BY a.name;
SELECT a.name,
COUNT(*) AS number_views,
AVG(r.rating) AS avg_rating
FROM renting as r
LEFT JOIN customers AS c
ON r.customer_id = c.customer_id
LEFT JOIN actsin as ai
ON r.movie_id = ai.movie_id
LEFT JOIN actors as a
ON ai.actor_id = a.actor_id
WHERE c.gender = 'male'
GROUP BY a.name
HAVING AVG(r.rating) IS NOT NULL
ORDER BY avg_rating DESC, number_views DESC;
| name | number_views | avg_rating |
|--------------------|--------------|------------|
| Ray Romano | 3 | 10.00 |
| Sean Bean | 2 | 10.00 |
| Leonardo DiCaprio | 3 | 9.33 |
| Christoph Waltz | 3 | 9.33 |
Toma de decisiones basada en datos en SQL