SQL Intermediário
Jasmin Ludolf
Data Science Content Developer, DataCamp
+, -, * e /
SELECT (4 + 3);
|7|
SELECT (4 * 3);
|12|
SELECT (4 - 3);
|1|
SELECT (4 / 3);
|1|
SELECT (4 / 3);
|1|
SELECT (4.0 / 3.0);
|1.333...|
Funções de agregação

Aritmética

SELECT (gross - budget)
FROM films;
|?column?|
|--------|
|null |
|2900000 |
|null |
...
SELECT (gross - budget) AS profit
FROM films;
|profit |
|--------|
|null |
|2900000 |
|null |
...
SELECT MAX(budget), MAX(duration)
FROM films;
|max |max|
|-----------|---|
|12215500000|334|
SELECT MAX(budget) AS max_budget,
MAX(duration) AS max_duration
FROM films;
|max_budget |max_duration|
|-----------|------------|
|12215500000|334 |
FROMWHERESELECT (os aliases são definidos aqui)LIMIT
SELECT não podem ser usados na cláusula WHERE devido à ordem de execução.SELECT budget AS max_budget
FROM films
WHERE max_budget IS NOT NULL;
column "max_budget" does not exist
LINE 5: WHERE max_budget IS NOT NULL;
^
SQL Intermediário