SQL intermedio con IA
Jasmin Ludolf
Senior Data Science Content Developer
$$
SUM()AVG()MIN()MAX()$$

$$
$$
Instrucción: Muestra el número total de votos en todas las películas
SELECT SUM(num_votes) AS total_votes
FROM reviews;
|total_votes|
|-----------|
|419507814 |
Instrucción: ¿Cuál es el número promedio de votos por película?
SELECT AVG(num_votes) AS average_votes_per_film
FROM reviews;
|average_votes_per_film|
|----------------------|
|84441.991545893720 |
Instrucción: ¿Cuál es el número promedio de votos por película redondeado?
SELECT ROUND(AVG(num_votes)) AS avg_votes
FROM reviews;
|avg_votes|
|---------|
|84442 |
ROUND(AVG(num_votes), 1)
84442.0
ROUND(AVG(num_votes), 2)
84441.99
ROUND(AVG(num_votes), -2)
84400
Instrucción: ...redondeado a un decimal
SELECT ROUND(AVG(num_votes), 1) AS avg_votes
FROM reviews;
|avg_votes|
|---------|
|84442.0 |
Instrucción: ...redondeado al centenar más cercano
SELECT ROUND(AVG(num_votes), -2) AS avg_votes
FROM reviews;
|avg_votes|
|---------|
|84400 |
Instrucción: Muestra el presupuesto promedio redondeado por idioma, ordenado por el más alto primero
SELECT language, ROUND(AVG(budget)) AS average_budget
FROM films
GROUP BY language
ORDER BY average_budget DESC;
|language |average_budget|
|---------|--------------|
|Greek | |
|Kannada | |
|Polish | |
|Korean |2741550000 |
...
Instrucción: Muestra los presupuestos más bajos y más altos por país, ordenados alfabéticamente
SELECT country,
MIN(budget) AS lowest_budget,
MAX(budget) AS highest_budget
FROM films
GROUP BY country
ORDER BY country;
|country |lowest_budget|highest_budget|
|-----------|-------------|--------------|
|Afghanistan|46000 |46000 |
|Argentina |800000 |2000000 |
|Aruba |35000000 |35000000 |
...
$$
$$
Solo campos numéricos
SUM()AVG()Varios tipos de datos
MIN()MAX()COUNT()$$
Mínimo <-> Máximo
SELECT MIN(language) AS min_language
FROM films;
|min_language|
|------------|
|Aboriginal |
SELECT MAX(language) AS max_language
FROM films;
|max_language|
|------------|
|Zulu |
SELECT SUM(budget) AS total_budget
...
SELECT AVG(budget) AS average_budget
...
SELECT country,
MIN(budget) AS lowest_budget,
MAX(budget) AS highest_budget
...
SELECT AVG(num_user), AVG(num_critic)
FROM reviews;
|avg |avg |
|275.6...|141.9...|
SELECT country,
MIN(budget) AS lowest_budget,
MAX(budget) AS highest_budget
FROM films
GROUP BY country
ORDER BY country;


SQL intermedio con IA