Subqueries in de FROM-instructie

Gegevens manipuleren in SQL

Mona Khalil

Data Scientist, Greenhouse Software

Subqueries in FROM

  • Herstructureer en transformeer je data
    • Transformeer data van lang naar breed voor selectie
    • Prefilter data
  • Bereken aggregaten van aggregaten
    • Welke 3 teams hebben het hoogste gemiddelde van thuisdoelpunten?
      1. Bereken de AVG voor elk team
      2. Neem de 3 hoogste AVG-waarden
Gegevens manipuleren in SQL

FROM subqueries...

SELECT
  t.team_long_name AS team,
  AVG(m.home_goal) AS home_avg
FROM match AS m
LEFT JOIN team AS t
ON m.hometeam_id = t.team_api_id
WHERE season = '2011/2012'
GROUP BY team;
| team                 | home_avg         |
|----------------------|------------------|
| 1. FC Köln           | 1.13725490196078 |
| 1. FC Nürnberg       | 1.27058823529412 |
| 1. FSV Mainz 05      | 1.43697478991597 |
| AC Ajaccio           | 1.12280701754386 |
Gegevens manipuleren in SQL

...naar hoofdqueries!


FROM (SELECT
          t.team_long_name AS team,
          AVG(m.home_goal) AS home_avg
      FROM match AS m
      LEFT JOIN team AS t
      ON m.hometeam_id = t.team_api_id
      WHERE season = '2011/2012'
      GROUP BY team)
Gegevens manipuleren in SQL

...naar hoofdqueries!


FROM (SELECT
          t.team_long_name AS team,
          AVG(m.home_goal) AS home_avg
      FROM match AS m
      LEFT JOIN team AS t
      ON m.hometeam_id = t.team_api_id
      WHERE season = '2011/2012'
      GROUP BY team) AS subquery
Gegevens manipuleren in SQL

...naar hoofdqueries!

SELECT team, home_avg
FROM (SELECT
          t.team_long_name AS team,
          AVG(m.home_goal) AS home_avg
      FROM match AS m
      LEFT JOIN team AS t
      ON m.hometeam_id = t.team_api_id
      WHERE season = '2011/2012'
      GROUP BY team) AS subquery
Gegevens manipuleren in SQL

...naar hoofdqueries!

SELECT team, home_avg
FROM (SELECT
          t.team_long_name AS team,
          AVG(m.home_goal) AS home_avg
      FROM match AS m
      LEFT JOIN team AS t
      ON m.hometeam_id = t.team_api_id
      WHERE season = '2011/2012'
      GROUP BY team) AS subquery
ORDER BY home_avg DESC
LIMIT 3;
| team           | home_avg |
|----------------|----------|
| FC Barcelona   | 3.8421   |
| Real Madrid CF | 3.6842   |
| PSV            | 3.3529   |
Gegevens manipuleren in SQL

Dingen om te onthouden

  • Je kunt meerdere subqueries maken in één FROM-instructie

    • Geef ze een alias!
    • Join ze!
  • Je kunt een subquery joinen met een tabel in FROM

    • Voeg een kolom toe in beide tabellen!
Gegevens manipuleren in SQL

Laten we oefenen!

Gegevens manipuleren in SQL

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