Cross field validation

Pulizia dei dati in R

Maggie Matsui

Content Developer @ DataCamp

What is cross field validation?

Cross field validation = a sanity check
Does this value make sense based on other values?

A screenshot from a news channel. Results of a poll asking, "Should Scotland be independent?". Yes is 52% of the answers, No is 58% of the answers.

¹ https://www.buzzfeednews.com/article/katienotopoulos/graphs-that-lied-to-us

Credit card data

head(credit_cards)

  date_opened dining_cb groceries_cb  gas_cb total_cb acct_age
1  2018-07-05     26.08        83.43   78.90   188.41        1
2  2016-01-23   1309.33         4.46 1072.25  2386.04        4
3  2016-03-25    205.84       119.20  800.62  1125.66        4
4  2018-06-20     14.00        16.37   18.41    48.78        1
5  2017-02-08     98.50       283.68  281.70   788.33        3
6  2014-11-18    889.28      2626.34 2973.62  6489.24        5

Validating numbers

credit_cards %>% 
  select(dining_cb:total_cb)

   dining_cb groceries_cb  gas_cb total_cb
1      26.08        83.43   78.90   188.41
2    1309.33         4.46 1072.25  2386.04
3     205.84       119.20  800.62  1125.66
4      14.00        16.37   18.41    48.78
5      98.50       283.68  281.70   788.33
6     889.28      2626.34 2973.62  6489.24

Validating numbers

credit_cards %>%

  mutate(theoretical_total = dining_cb + groceries_cb + gas_cb) %>%

  filter(theoretical_total != total_cb) %>%
  select(dining_cb:theoretical_total)

  dining_cb groceries_cb  gas_cb total_cb theoretical_total
1     98.50       283.68  281.70   788.33            663.88
2   3387.53       363.85 2706.42  4502.94           6457.80

Validating date and age

credit_cards %>%
  select(date_opened, acct_age)

   date_opened acct_age
1   2018-07-05        1
2   2016-01-23        4
3   2016-03-25        4
4   2018-06-20        1
5   2017-02-08        3
6   2014-11-18        5

Calculating age

library(lubridate)
date_difference <- as.Date("2015-09-04") %--% today()
date_difference

2015-09-04 UTC--2020-03-09 UTC

as.numeric(date_difference, "years")

4.511978

floor(as.numeric(date_difference, "years"))

Validating age

credit_cards %>%
  mutate(theor_age = floor(as.numeric(date_opened %--% today(), "years"))) %>%
  filter(theor_age != acct_age)

  date_opened acct_age dining_cb groceries_cb  gas_cb total_cb theor_age
1  2016-03-25        4    814.34       471.58 3167.41  4453.33         3
2  2018-03-06        3    238.48       186.05  213.84   638.37         2

What next?

On the left, a trash can to represent dropping data. In the middle, a question mark to represent set to missing and impute. On the right, some squares linked by lines containing check marks and x's to represent applying rules from domain knowledge.

Let's practice!

Pulizia dei dati in R