Werken met georuimtelijke data in Python
Joris Van den Bossche
Open source software developer and teacher, GeoPandas maintainer

Bron: QGIS-documentatie



import rasterio
import rasterio
src = rasterio.open("DEM_world.tif")
Metadata:
src.count
1
src.width, src.height
(4320, 2160)
array = src.read()
Standaard numpy-array:
array
array([[[-4290, -4290, -4290, ..., -4290, -4290, -4290],
[-4278, -4278, -4278, ..., -4278, -4278, -4278],
[-4269, -4269, -4269, ..., -4269, -4269, -4269],
...,
[ 2804, 2804, 2804, ..., 2804, 2804, 2804],
[ 2804, 2804, 2804, ..., 2804, 2804, 2804],
[ 2804, 2804, 2804, ..., 2804, 2804, 2804]]], dtype=int16)
Met de methode rasterio.plot.show():
import rasterio.plot
rasterio.plot.show(src, cmap='terrain')


rasterstats: Samenvattende statistieken van geospatiale rasterdata op basis van vectorgeometrieën (https://github.com/perrygeo/python-rasterstats)
Voor puntvectoren:
rasterstats.point_query(geometries, "path/to/raster",
interpolation='nearest'|'bilinear')
Voor polygoonvectoren:
rasterstats.zonal_stats(geometries, "path/to/raster",
stats=['min', 'mean', 'max'])
result = rasterstats.zonal_stats(countries.geometry, "DEM_gworld.tif", stats=['mean'])countries['mean_elevation'] = pd.DataFrame(result)countries.sort_values('mean_elevation', ascending=False).head()
name continent geometry mean_elevation
157 Tajikistan Asia POLYGON ((74.98 37.41, ... 3103.231105
85 Kyrgyzstan Asia POLYGON ((80.25 42.34, ... 2867.717142
24 Bhutan Asia POLYGON ((91.69 27.77, ... 2573.559846
119 Nepal Asia POLYGON ((81.11 30.18, ... 2408.907816
6 Antarctica Antarctica (POLYGON ((-59.57 -80.04... 2374.075028
.. ... ... ... ...
Werken met georuimtelijke data in Python