Pengantar Statistika di Python
Maggie Matsui
Content Developer, DataCamp




Nilai harapan: mean dari distribusi probabilitas
Nilai harapan lemparan dadu adil = $(1 \times \frac{1}{6}) + (2 \times \frac{1}{6}) +(3 \times \frac{1}{6}) +(4 \times \frac{1}{6}) +(5 \times \frac{1}{6}) +(6 \times \frac{1}{6}) = 3{,}5$

$$P(\text{lempar dadu}) \le 2 = ~?$$

$$P(\text{lempar dadu}) \le 2 = 1/3$$


Nilai harapan lemparan dadu tidak merata = $(1 \times \frac{1}{6}) +(2 \times 0) +(3 \times \frac{1}{3}) +(4 \times \frac{1}{6}) +(5 \times \frac{1}{6}) +(6 \times \frac{1}{6}) = 3{,}67$

$$P(\text{lempar dadu tidak merata}) \le 2 = ~?$$

$$P(\text{lempar dadu tidak merata}) \le 2 = 1/6$$

Jelaskan probabilitas untuk hasil diskret

Distribusi seragam diskret

print(die)
number prob
0 1 0.166667
1 2 0.166667
2 3 0.166667
3 4 0.166667
4 5 0.166667
5 6 0.166667
np.mean(die['number'])
3.5
rolls_10 = die.sample(10, replace = True)
rolls_10
number prob
0 1 0.166667
0 1 0.166667
4 5 0.166667
1 2 0.166667
0 1 0.166667
0 1 0.166667
5 6 0.166667
5 6 0.166667
...
rolls_10['number'].hist(bins=np.linspace(1,7,7))
plt.show()


np.mean(rolls_10['number']) = 3.0

mean(die['number']) = 3.5

np.mean(rolls_100['number']) = 3.4

mean(die['number']) = 3.5

np.mean(rolls_1000['number']) = 3.48

mean(die['number']) = 3.5
Saat ukuran sampel bertambah, rata-rata sampel mendekati nilai harapan.
| Ukuran sampel | Rata-rata |
|---|---|
| 10 | 3,00 |
| 100 | 3,40 |
| 1000 | 3,48 |
Pengantar Statistika di Python