Menganalisis Data Bisnis di SQL
Michel Semaan
Data Scientist
DATE_TRUNC('quarter', '2018-08-13') → '2018-07-01 00:00:00+00:00''2018-07-01 00:00:00+00:00' :: DATE → '2018-07-01'Tanggal dalam laporan
'2018-08-13', kurang mudah dibaca'2018-08-13' menjadi 'Friday 13, August 2018'?Solusi
TO_CHAR('2018-08-13', 'FMDay DD, FMMonth YYYY') → 'Friday 13, August 2018'TO_CHAR(DATE, TEXT) → TEXT (string tanggal terformat)Contoh: Dy → Singkatan nama hari (Mon, Tues, dll.)
TO_CHAR('2018-06-01', 'Dy') → 'Fri'TO_CHAR('2018-06-02', 'Dy') → 'Sat'Pola dalam format akan diganti sesuai komponennya; karakter lain tetap
DD → Nomor hari (01 - 31)TO_CHAR('2018-06-01', 'Dy - DD') → 'Fri - 01'TO_CHAR('2018-06-02', 'Dy - DD') → 'Sat - 02'| Pola | Deskripsi |
|---|---|
FMDay |
Nama hari lengkap (Monday, Tuesday, dll.) |
MM |
Bulan ke (01 - 12) |
Mon |
Singkatan nama bulan (Jan, Feb, dll.) |
FMMonth |
Nama bulan lengkap (January, February, dll.) |
YY |
2 digit terakhir tahun (18, 19, dll.) |
YYYY |
Tahun 4 digit penuh (2018, 2019, dll.) |
Dokumentasi: https://www.postgresql.org/docs/9.6/functions-formatting.html
Kueri
SELECT DISTINCT
order_date,
TO_CHAR(order_date,
'FMDay DD, FMMonth YYYY') AS format_1,
TO_CHAR(order_date,
'Dy DD Mon/YYYY') AS format_2
FROM orders
ORDER BY order_date ASC
LIMIT 3;
Hasil
order_date format_1 format_2
---------- ---------------------- ---------------
2018-06-01 Friday 01, June 2018 Fri 01/Jun 2018
2018-06-02 Saturday 02, June 2018 Sat 02/Jun 2018
2018-06-02 Sunday 03, June 2018 Sun 03/Jun 2018
SUM(...) OVER (...): Menghitung total kumulatif kolomSUM(registrations) OVER (ORDER BY registration_month) menghitung total kumulatif pendaftaranLAG(...) OVER (...): Mengambil nilai baris sebelumnyaLAG(mau) OVER (ORDER BY active_month) mengembalikan MAU bulan sebelumnyaRANK() OVER (...): Memberi peringkat tiap baris berdasarkan posisinya dalam urutan terurutRANK() OVER (ORDER BY revenue DESC) memberi peringkat pengguna, restoran, atau bulan menurut pendapatan yang dihasilkanKueri
SELECT
user_id,
SUM(meal_price * order_quantity) AS revenue
FROM meals
JOIN orders ON meals.meal_id = orders.meal_id
GROUP BY user_id
ORDER BY revenue DESC
LIMIT 3;
Hasil
user_id revenue
------- -------
18 626
76 553.25
73 537
Kueri
WITH user_revenues AS (
SELECT
user_id,
SUM(meal_price * order_quantity) AS revenue
FROM meals
JOIN orders ON meals.meal_id = orders.meal_id
GROUP BY user_id)
SELECT
user_id,
RANK() OVER (ORDER BY revenue DESC)
AS revenue_rank
FROM user_revenues
ORDER BY revenue_rank DESC
LIMIT 3;
Hasil
user_id revenue_rank
------- ------------
18 1
76 2
73 3
Menganalisis Data Bisnis di SQL