Analisis Deret Waktu di SQL Server
Maham Faisal Khan
Senior Data Science Content Developer
DATEFROMPARTS(year, month, day)
TIMEFROMPARTS(hour, minute, second, fraction, precision)
DATETIMEFROMPARTS(year, month, day, hour, minute, second, ms)
DATETIME2FROMPARTS(year, month, day, hour, minute, second, fraction, precision)
SMALLDATETIMEFROMPARTS(year, month, day, hour, minute)
DATETIMEOFFSETFROMPARTS(year, month, day, hour, minute, second, fraction, hour_offset, minute_offset, precision)
SELECT
DATETIMEFROMPARTS(1918, 11, 11, 05, 45, 17, 995) AS DT,
DATETIME2FROMPARTS(1918, 11, 11, 05, 45, 17, 0, 0) AS DT20,
DATETIME2FROMPARTS(1918, 11, 11, 05, 45, 17, 995, 3) AS DT23,
DATETIME2FROMPARTS(1918, 11, 11, 05, 45, 17, 9951234, 7) AS DT27;
| DT | DT20 | DT23 | DT27 |
|---|---|---|---|
| 1918-11-11 05:45:17.997 | 1918-11-11 05:45:17 | 1918-11-11 05:45:17.995 | 1918-11-11 05:45:17.9951234 |
SELECT
DATETIMEOFFSETFROMPARTS(2009, 08, 14, 21,
00, 00, 0, 5, 30, 0) AS IST,
DATETIMEOFFSETFROMPARTS(2009, 08, 14, 21,
00, 00, 0, 5, 30, 0)
AT TIME ZONE 'UTC' AS UTC;
| IST | UTC |
|---|---|
| 2009-08-14 21:00:00 +05:30 | 2009-08-14 15:30:00 +00:00 |
DATEFROMPARTS(1999, 12, NULL)
DATEFROMPARTS(10000, 01, 01)
DATETIME2FROMPARTS(1918, 11, 11, 05, 45, 17, 995, 0)
NULL
Tidak dapat membentuk tipe data date, beberapa argumen memiliki nilai tidak valid.
Tidak dapat membentuk tipe data datetime2, beberapa argumen memiliki nilai tidak valid.
Analisis Deret Waktu di SQL Server