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Viết Hàm và Thủ Tục Lưu Trữ trong SQL Server

Meghan Kwartler

IT Consultant

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SELECT 
  DATENAME(weekday, StartDate) AS 'DayOfWeek', 
  SUM(Duration) AS TotalDuration 
FROM CapitalBikeShare 
GROUP BY DATENAME(weekday, StartDate) 
ORDER BY DATENAME(weekday, StartDate)
+-----------+---------------+
| DayOfWeek | TotalDuration |
|-----------+---------------|
| Friday    | 7264870       |
| Monday    | 6571322       |
| Saturday  | 13411642      |
| Sunday    | 8418226       |
| Thursday  | 8646359       |
| Tuesday   | 3788474       |
| Wednesday | 3525955       |
+-----------+---------------|
Viết Hàm và Thủ Tục Lưu Trữ trong SQL Server

Sắp xếp theo thứ tự ngày trong tuần

SELECT DATENAME(weekday, StartDate) as 'DayOfWeek', 
SUM(Duration) as TotalDuration
FROM CapitalBikeShare
GROUP BY DATENAME(WEEKDAY, StartDate)
ORDER BY 
     CASE WHEN Datename(WEEKDAY, StartDate) = 'Sunday' THEN 1
          WHEN Datename(WEEKDAY, StartDate) = 'Monday' THEN 2
          WHEN Datename(WEEKDAY, StartDate) = 'Tuesday' THEN 3
          WHEN Datename(WEEKDAY, StartDate) = 'Wednesday' THEN 4
          WHEN Datename(WEEKDAY, StartDate) = 'Thursday' THEN 5
          WHEN Datename(WEEKDAY, StartDate) = 'Friday' THEN 6
          WHEN Datename(WEEKDAY, StartDate) = 'Saturday' THEN 7
    END ASC;
+-----------+---------------+
| DayOfWeek | TotalDuration |
|-----------+---------------|
| Sunday    | 8418226       |
| Monday    | 6571322       |
| Tuesday   | 3788474       |
| Wednesday | 3525955       |
| Thursday  | 8646359       |
| Friday    | 7264870       |
| Saturday  | 13411642      |
+-----------+---------------|
Viết Hàm và Thủ Tục Lưu Trữ trong SQL Server
SELECT TOP 5 
FORMAT(CAST(StartDate as Date), 'd', 'de-de')
AS 'German Date',
FORMAT(CAST(StartDate as Date), 'd', 'en-us')
AS 'US Eng Date',
FORMAT(Sum(Duration), 'n', 'de-de')
AS 'German Duration',
FORMAT(SUM(Duration), 'n', 'en-us')
AS 'US Eng Duration',
FORMAT(SUM(Duration),'#,0.00') 
AS 'Custom Numeric'
FROM CapitalBikeShare
GROUP BY CAST(StartDate as Date)
+-------------+-------------+-----------------+-----------------+----------------+
| German Date | US Eng Date | German Duration | US Eng Duration | Custom Numeric |
|-------------+-- ----------+-----------------+-----------------+----------------|
|  09.03.2018 | 3/9/2018    | 1.141.796,00    | 1,141,796.00    | 1,141,796.00   |
|  18.03.2018 | 3/18/2018   | 3.074.907,00    | 3,074,907.00    | 3,074,907.00   |
|  12.03.2018 | 3/12/2018   | 1.088.822,00    | 1,088,822.00    | 1,088,822.00   |
|  26.03.2018 | 3/26/2018   | 2.160.609,00    | 2,160,609.00    | 2,160,609.00   |
|  29.03.2018 | 3/29/2018   | 3.552.955,00    | 3,552,955.00    | 3,552,955.00   |
+-------------+-------------+-----------------+-----------------+----------------|
Viết Hàm và Thủ Tục Lưu Trữ trong SQL Server
SELECT DATENAME(weekday, StartDate) 
AS 'DayOfWeek', 
FORMAT(SUM(Duration),'#,0.00') 
AS 'TotalDuration'
FROM CapitalBikeShare
GROUP BY DATENAME(WEEKDAY, StartDate)
ORDER BY 
     CASE
          WHEN Datename(WEEKDAY, StartDate) = 'Sunday' THEN 1
          WHEN Datename(WEEKDAY, StartDate) = 'Monday' THEN 2
          WHEN Datename(WEEKDAY, StartDate) = 'Tuesday' THEN 3
          WHEN Datename(WEEKDAY, StartDate) = 'Wednesday' THEN 4
          WHEN Datename(WEEKDAY, StartDate) = 'Thursday' THEN 5
          WHEN Datename(WEEKDAY, StartDate) = 'Friday' THEN 6
          WHEN Datename(WEEKDAY, StartDate) = 'Saturday' THEN 7
    END ASC
+-----------+---------------+
| DayOfWeek | TotalDuration |
|-----------+---------------|
| Sunday    | 8,418,226.00  |
| Monday    | 6,571,322.00  |
| Tuesday   | 3,788,474.00  |
| Wednesday | 3,525,955.00  |
| Thursday  | 8,646,359.00  |
| Friday    | 7,264,870.00  |
| Saturday  | 13,411,642.00 |
+-----------+---------------+
Viết Hàm và Thủ Tục Lưu Trữ trong SQL Server

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Viết Hàm và Thủ Tục Lưu Trữ trong SQL Server

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