보고서 중복

SQL로 리포트 만들기

Tyler Pernes

Learning & Development Consultant

중복의 원인

SELECT p.id, SUM(points) AS points, SUM(matches_win) AS matches_won
FROM points AS p
JOIN matches AS m ON p.id = m.id
GROUP BY p.id;

중복의 원인

+-----+--------+--------------+
| id  | points | matches_won  |
|-----|--------|--------------|
| 1   | 156    | 10           |
+-----+--------+--------------+

¹ points 값이 실제보다 3배(여기서는 156)로 증가합니다.

중복의 원인

중간 테이블
+-----+------+--------------+---------+ 
| id  | year | matches_won  | points  |
|-----|------|--------------|---------|    
| 1   | 2016 | 5            | 52      |
| 1   | 2017 | 2            | 52      |  
| 1   | 2018 | 3            | 52      |
+-----+------+--------------+---------+

중복의 원인

중간 테이블
+-----+------+--------------+---------+ 
| id  | year | matches_won  | points  |
|-----|------|--------------|---------|    
| 1   | 2016 | 5            | 52      | <--
| 1   | 2017 | 2            | 52      | <-- SUM(points) = 52 x 3 = 156
| 1   | 2018 | 3            | 52      | <-- 
+-----+------+--------------+---------+

중복 해결 방법

1. 집계를 제거

SELECT p.id, points, SUM(matches_won) AS matches_won
FROM points AS p
JOIN matches AS m ON p.id = m.id
GROUP BY p.id, points;

+-----+--------+--------------+
| id  | points | matches_won  |
|-----|--------|--------------|
| 1   | 52     | 10           |
+-----+--------+--------------+

중복 해결 방법

2. JOIN에 필드 추가

SELECT p.id, SUM(points) AS points, SUM(matches_win) AS matches_won
FROM points AS p
JOIN matches AS m ON p.id = m.id AND p.year = m.year
GROUP BY p.id;

중복 해결 방법

2. JOIN에 필드 추가

SELECT p.id, SUM(points) AS points, SUM(matches_win) AS matches_won
FROM points AS p
JOIN matches AS m ON p.id = m.id AND p.year = m.year
GROUP BY p.id;

중복 해결 방법

SELECT id, SUM(matches_won)
FROM matches
GROUP BY id;

+-----+--------------+
| id  | matches_won  |
|-----|--------------|
| 1   | 10           |
| 2   | 7            |
+-----+--------------+

중복 해결 방법

3. 하위 쿼리로 롤업

SELECT p.id, points, matches_won
FROM points AS p
JOIN 
    (SELECT id, SUM(matches_won) AS matches_won
    FROM matches
    GROUP BY id) AS m 
ON p.id = m.id;

중복 해결 방법

집계를 제거
JOIN에 필드 추가
하위 쿼리로 롤업

중복 식별하기

원본 테이블의 값:

SELECT SUM(points) AS total_points
FROM points;

total_points = 52

쿼리의 값:

SELECT SUM(points) AS total_points
FROM   
    (SELECT p.id, SUM(points) AS points
    FROM points AS p
    JOIN matches AS m ON p.id = m.id
    GROUP BY p.id) AS subquery;

total_points = 156

챕터 목표

연습해 봅시다!

SQL로 리포트 만들기