Pythonで学ぶデータクリーニング
Adel Nehme
Content Developer @DataCamp
I) 値の不一致
'married', 'Maried', 'UNMARRIED', 'not married'..'married ', ' married '..II) 過多なカテゴリを少数に集約
0-20K, 20-40K など'rich', 'poor' の2区分にIII) データ型が category であることの確認(第1章で学習)
大文字小文字: 'married', 'Married', 'UNMARRIED', 'unmarried'..
# 結婚状況列を取得
marriage_status = demographics['marriage_status']
marriage_status.value_counts()
unmarried 352
married 268
MARRIED 204
UNMARRIED 176
dtype: int64
# DataFrameで件数集計
marriage_status.groupby('marriage_status').count()
household_income gender
marriage_status
MARRIED 204 204
UNMARRIED 176 176
married 268 268
unmarried 352 352
# 大文字化marriage_status['marriage_status'] = marriage_status['marriage_status'].str.upper() marriage_status['marriage_status'].value_counts()
UNMARRIED 528
MARRIED 472
# 小文字化marriage_status['marriage_status'] = marriage_status['marriage_status'].str.lower() marriage_status['marriage_status'].value_counts()
unmarried 528
married 472
前後の空白: 'married ', 'married', 'unmarried', ' unmarried'..
# 結婚状況列を取得
marriage_status = demographics['marriage_status']
marriage_status.value_counts()
unmarried 352
unmarried 268
married 204
married 176
dtype: int64
# 余分な空白を削除
demographics = demographics['marriage_status'].str.strip()
demographics['marriage_status'].value_counts()
unmarried 528
married 472
データからカテゴリを作成: income 列から income_group 列を作る。
# Using qcut()
import pandas as pd
group_names = ['0-200K', '200K-500K', '500K+']
demographics['income_group'] = pd.qcut(demographics['household_income'], q = 3,
labels = group_names)
# Print income_group column
demographics[['income_group', 'household_income']]
category household_income
0 200K-500K 189243
1 500K+ 778533
..
データからカテゴリを作成: income 列から income_group 列を作る。
# Using cut() - create category ranges and names
ranges = [0,200000,500000,np.inf]
group_names = ['0-200K', '200K-500K', '500K+']
# Create income group column
demographics['income_group'] = pd.cut(demographics['household_income'], bins=ranges,
labels=group_names)
demographics[['income_group', 'household_income']]
category Income
0 0-200K 189243
1 500K+ 778533
カテゴリをより少数へ集約: カテゴリ列の区分を減らす。
operating_system 列の値: 'Microsoft', 'MacOS', 'IOS', 'Android', 'Linux'
operating_system 列の目標: 'DesktopOS', 'MobileOS'
# Create mapping dictionary and replace
mapping = {'Microsoft':'DesktopOS', 'MacOS':'DesktopOS', 'Linux':'DesktopOS',
'IOS':'MobileOS', 'Android':'MobileOS'}
devices['operating_system'] = devices['operating_system'].replace(mapping)
devices['operating_system'].unique()
array(['DesktopOS', 'MobileOS'], dtype=object)
Pythonで学ぶデータクリーニング