SQL Server 入門
John MacKintosh
Instructor
LEFT と RIGHT 結合が必要かLEFT と RIGHT 結合が必要か入院テーブル
+------------+----------+
| Patient_ID | Admitted |
|------------+----------|
| 1 | 1 |
| 2 | 1 |
| 3 | 1 |
| 4 | 1 |
| 5 | 1 |
+------------+----------+
退院テーブル
+------------+------------+
| Patient_ID | Discharged |
|------------+------------|
| 1 | 1 |
| 3 | 1 |
| 4 | 1 |
+------------+------------+
INNER JOIN:
+------------+----------+------------|
| Patient_ID | Admitted | Discharged |
|------------+----------|------------|
| 1 | 1 | 1 |
| 3 | 1 | 1 |
| 4 | 1 | 1 |
+------------+----------+------------+
LEFT JOIN:
+------------+----------+------------|
| Patient_ID | Admitted | Discharged |
|------------+----------|------------|
| 1 | 1 | 1 |
| 2 | 1 | NULL |
| 3 | 1 | 1 |
| 4 | 1 | 1 |
| 5 | 1 | NULL |
+------------+----------+------------+
SELECT
Admitted.Patient_ID,
Admitted,
Discharged
FROM Admitted
LEFT JOIN Discharged ON Discharged.Patient_ID = Admitted.Patient_ID;
SELECT
Admitted.Patient_ID,
Admitted,
Discharged
FROM Admitted
LEFT JOIN Discharged ON Discharged.Patient_ID = Admitted.Patient_ID;
+------------+----------+------------|
| Patient_ID | Admitted | Discharged |
|------------+----------|------------|
| 1 | 1 | 1 |
| 2 | 1 | NULL |
| 3 | 1 | 1 |
| 4 | 1 | 1 |
| 5 | 1 | NULL |
+------------+----------+------------+
SELECT
Admitted.Patient_ID,
Admitted,
Discharged
FROM Discharged
RIGHT JOIN Admitted ON Admitted.Patient_ID = Discharged.Patient_ID;
SELECT
Admitted.Patient_ID,
Admitted,
Discharged
FROM Discharged
RIGHT JOIN Admitted ON Admitted.Patient_ID = Discharged.Patient_ID;
+------------+----------+------------|
| Patient_ID | Admitted | Discharged |
|------------+----------|------------|
| 1 | 1 | 1 |
| 2 | 1 | NULL |
| 3 | 1 | 1 |
| 4 | 1 | 1 |
| 5 | 1 | NULL |
+------------+----------+------------+
INNER JOIN: 一致する行のみを返すLEFT JOIN(または RIGHT JOIN): 主テーブルの全行+結合先の一致NULL: 一致なしの場合に表示LEFT JOIN と RIGHT JOIN は入れ替え可能SQL Server 入門