Snowflake SQL 입문
George Boorman
Senior Curriculum Manager, DataCamp

NATURAL JOIN은 동일한 컬럼을 자동 매칭하고 중복 컬럼을 제거합니다.Syntax:
SELECT ...
FROM <table_one> [
{
| NATURAL [ { LEFT | RIGHT | FULL } [ OUTER ] ]
}
]
JOIN <table_two>
[ ... ]
NATURAL JOIN 없이SELECT *
FROM pizzas AS p
JOIN pizza_type AS t
ON t.pizza_type_id = p.pizza_type_id

NATURAL JOIN 사용SELECT *
FROM pizzas AS p
NATURAL JOIN pizza_type AS t

❌ 허용되지 않음 ❌
select *
FROM pizzas AS p
NATURAL JOIN pizza_type AS t
ON t.pizza_type_id = p.pizza_type_id

$$
✅ 허용됨 ✅
WHERE 절SELECT *
FROM pizzas AS p
NATURAL JOIN pizza_type AS t
WHERE pizza_type_id = 'bbq_ckn'
LATERAL JOIN: FROM의 하위쿼리가 앞선 테이블/뷰의 컬럼을 참조할 수 있게 합니다.Syntax:
SELECT ...
FROM <left_hand_expression> , --
LATERAL
(<right_hand_expression>)
left_hand_expression - 테이블, 뷰, 또는 서브쿼리
right_hand_expression - 인라인 뷰 또는 서브쿼리
SELECT p.pizza_id, lat.name, lat.category FROM pizzas AS p,LATERAL -- 키워드 LATERAL ( SELECT * FROM pizza_type AS t-- 외부 쿼리 컬럼 참조: p.pizza_type_id WHERE p.pizza_type_id = t.pizza_type_id) AS lat
SELECT
*
FROM orders AS o,
LATERAL (
-- total_spent 계산 서브쿼리
SELECT
SUM(p.price * od.quantity) AS total_spent
FROM order_details AS od
JOIN pizzas AS p
ON od.pizza_id = p.pizza_id
WHERE o.order_id = od.order_id
) AS t
ORDER BY o.order_id
Snowflake SQL 입문