Intermediate SQL Querying with AI
Jasmin Ludolf
Senior Data Science Content Developer
Prompt: Zobrazte počet filmů s rozpočtem a bez rozpočtu pro každý rok
SELECT
release_year,
COUNT(CASE WHEN budget IS NOT NULL THEN 1 END) AS films_with_budget,
COUNT(CASE WHEN budget IS NULL THEN 1 END) AS films_without_budget
FROM films
GROUP BY release_year;
|release_year|films_with_budget|films_without_budget|
|------------|-----------------|--------------------|
|1964 |10 |0 |
|1969 |9 |1 |
...

Prompt: Zobrazte počet filmů s rozpočtem a bez rozpočtu pro každý rok
SELECT
release_year,
COUNT(CASE WHEN budget IS NOT NULL THEN 1 END) AS films_with_budget,
COUNT(CASE WHEN budget IS NULL THEN 1 END) AS films_without_budget
FROM films
GROUP BY release_year;
|release_year|films_with_budget|films_without_budget|
|------------|-----------------|--------------------|
|1964 |10 |0 |
|1969 |9 |1 |
...
1Prompt: Zobrazte počet filmů s rozpočtem a bez rozpočtu pro každý rok
SELECT
release_year,
SUM(CASE WHEN budget IS NOT NULL THEN 1 ELSE 0 END) AS films_with_budget,
SUM(CASE WHEN budget IS NULL THEN 1 ELSE 0 END) AS films_without_budget
FROM films
GROUP BY release_year;
|release_year|films_with_budget|films_without_budget|
|------------|-----------------|--------------------|
|1964 |10 |0 |
|1969 |9 |1 |
...
Prompt: Zobrazte počet filmů s rozpočtem a bez rozpočtu pro každý rok
SELECT
release_year,
COUNT(CASE WHEN budget IS NOT NULL THEN 1 END) AS films_with_budget,
COUNT(CASE WHEN budget IS NULL THEN 1 END) AS films_without_budget
FROM films
GROUP BY release_year;
NULLs jsou ve sloupci films_without_budgetWHEREPrompt: Pro každý rok po roce 2000 s alespoň 5 filmy s údaji o rozpočtu rozdělte filmy na Vysoký rozpočet (nad 1 milion) a Nízký rozpočet (1 milion nebo méně) a zobrazte počty pro každou kategorii, seřazené podle roku, top 10 výsledků
SELECT release_year,COUNT(CASE WHEN budget > 1000000 THEN 1 END) AS high_budget_count, COUNT(CASE WHEN budget <= 1000000 THEN 1 END) AS low_budget_countFROM filmsWHERE release_year > 2000 AND budget IS NOT NULLGROUP BY release_yearHAVING COUNT(*) >= 5ORDER BY release_year LIMIT 10;
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Intermediate SQL Querying with AI