Poddotazy v SELECT

Manipulace s daty v SQL

Mona Khalil

Data Scientist, Greenhouse Software

Co vlastně vybíráme?

Vrací jedinou hodnotu
- Umožňuje porovnávat agregované hodnoty s jednotlivými

Využití v matematických výpočtech
- Odchylka od průměru

Poddotazy v SELECT

Výpočet celkového počtu zápasů napříč všemi sezonami

SELECT COUNT(id) FROM match;

Poddotazy v SELECT

SELECT
  season,
  COUNT(id) AS matches,
  12837 as total_matches
FROM match
GROUP BY season;

| season    | matches | total_matches |
|-----------|---------|---------------|
| 2011/2012 | 3220    | 12837         |
| 2012/2013 | 3260    | 12837         |
| 2013/2014 | 3032    | 12837         |
| 2014/2015 | 3325    | 12837         |

Poddotazy v SELECT

SELECT
  season,
  COUNT(id) AS matches,
  (SELECT COUNT(id) FROM match) as total_matches
FROM match
GROUP BY season;

| season    | matches | total_matches |
|-----------|---------|---------------|
| 2011/2012 | 3220    | 12837         |
| 2012/2013 | 3260    | 12837         |
| 2013/2014 | 3032    | 12837         |
| 2014/2015 | 3325    | 12837         |

Poddotazy v SELECT pro matematické výpočty

SELECT AVG(home_goal + away_goal) 
FROM match
WHERE season = '2011/2012';

2.72

SELECT
  date,
  (home_goal + away_goal) AS goals,
  (home_goal + away_goal) - 2.72 AS diff
FROM match
WHERE season = '2011/2012';

Poddotazy v SELECT

SELECT
  date,
  (home_goal + away_goal) AS goals,
  (home_goal + away_goal) - 
     (SELECT AVG(home_goal + away_goal) 
      FROM match
      WHERE season = '2011/2012') AS diff
FROM match
WHERE season = '2011/2012';

| date       | goals | diff              |
|------------|-------|-------------------|
| 2011-07-29 | 3     | 0.28354037267081  |
| 2011-07-30 | 2     | -0.71645962732919 |
| 2011-07-30 | 4     | 1.28354037267081  |
| 2011-07-30 | 1     | -1.71645962732919 |

Poddotazy v SELECT – na co nezapomenout

Musí vracet JEDINOU hodnotu
- Jinak dojde k chybě
Dbejte na správné umístění filtrů
- Filtrujte oba dotazy – hlavní i poddotaz!

SELECT
    date,
    (home_goal + away_goal) AS goals,
    (home_goal + away_goal) - 
       (SELECT AVG(home_goal + away_goal) 
        FROM match
        WHERE season = '2011/2012') AS diff
FROM match
WHERE season = '2011/2012';

Lass uns üben!

Manipulace s daty v SQL