统计学入门
George Boorman
Curriculum Manager, DataCamp
事件的概率是多少?
$$ P(\text{event}) = \frac{\text{事件发生的方式数}}{\text{所有可能结果总数}} $$
示例:抛硬币
$$ P(\text{正面}) = \frac{\text{得到正面的1种方式}}{\text{2种可能结果}} = \frac{1}{2} = 50\%$$



$$P(\text{Brian}) = \frac{1}{4} = 25\%$$


$$P(\text{Brian}) = \frac{1}{4} = 25\%$$
若第二个事件的概率不因第一个事件的结果而改变,则两事件相互独立。
| 订单号 | 产品类型 | 净数量 | 毛销售额 | 折扣 | 退货 | 净销售额 |
|---|---|---|---|---|---|---|
| 200 | Basket | 13 | 3744.0 | -316.80 | 0.00 | 3427.20 |
| 201 | Basket | 12 | 3825.0 | -201.60 | -288.0 | 3335.40 |
| 202 | Basket | 17 | 3035.0 | -63.25 | 0.00 | 2971.75 |
| 203 | Art & Sculpture | 47 | 2696.8 | -44.16 | 0.00 | 2652.64 |
| 204 | Basket | 17 | 2695.0 | -52.50 | -110.00 | 2532.50 |

| 产品类型 | 订单数 |
|---|---|
| Basket | 551 |
| Art & Sculpture | 337 |
| Jewelry | 210 |
| Kitchen | 161 |
| Home Decor | 131 |
| ... | ... |
| 合计 | 1767 |
$$P(Jewelry) = \frac{Order \ Count(Jewelry)}{Sum(Total \ Order \ Count)}$$
$$P(Jewelry) = \frac{210}{1767}$$
$$P(Jewelry) = 11.88 \%$$
| 产品类型 | 订单数 | 概率 |
|---|---|---|
| Basket | 551 | 31.18% |
| Art & Sculpture | 337 | 19.07% |
| Jewelry | 210 | 11.88% |
| Kitchen | 161 | 9.11% |
| Home Decor | 131 | 7.41% |
| ... | ... | ... |
| 合计 | 1767 | 100% |
统计学入门