列表推导式
Python 工具箱
Hugo Bowne-Anderson
Data Scientist at DataCamp
用 for 循环填充列表
nums = [12, 8, 21, 3, 16]new_nums = []for num in nums: new_nums.append(num + 1)print(new_nums)
[13, 9, 22, 4, 17]
一个列表推导式
nums = [12, 8, 21, 3, 16] new_nums = [num + 1 for num in nums]print(new_nums)
[13, 9, 22, 4, 17]
for 循环与列表推导式语法
new_nums = [num + 1 for num in nums]
for num in nums: new_nums.append(num + 1)print(new_nums)
[13, 9, 22, 4, 17]
配合 range() 的列表推导式
result = [num for num in range(11)]print(result)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
列表推导式
- 将构建列表的 for 循环压缩到一行
- 组成部分
- 可迭代对象
- 迭代变量（表示可迭代对象的成员）
- 输出表达式
嵌套循环 (1)
pairs_1 = []for num1 in range(0, 2): for num2 in range(6, 8): pairs_1.append((num1, num2))print(pairs_1)
[(0, 6), (0, 7), (1, 6), (1, 7)]
- 如何用列表推导式实现？
嵌套循环 (2)
pairs_2 = [(num1, num2) for num1 in range(0, 2) for num2 in range(6, 8)]print(pairs_2)
[(0, 6), (0, 7), (1, 6), (1, 7)]
- 权衡：可读性
Vamos praticar!
Python 工具箱
