Bucla for
Python intermediar
Hugo Bowne-Anderson
Data Scientist at DataCamp
Bucla for
for var in seq :
expression
- „pentru fiecare var din seq, execută expression"
fam
family.py
fam = [1.73, 1.68, 1.71, 1.89]print(fam)
[1.73, 1.68, 1.71, 1.89]
fam
family.py
fam = [1.73, 1.68, 1.71, 1.89]
print(fam[0])
print(fam[1])
print(fam[2])
print(fam[3])
1.73
1.68
1.71
1.89
Bucla for
for var in seq :
expression
family.py
fam = [1.73, 1.68, 1.71, 1.89]
for height in fam :
print(height)
Bucla for
for var in seq :
expression
family.py
fam = [1.73, 1.68, 1.71, 1.89]
for height in fam :
print(height)
# first iteration
# height = 1.73
1.73
Bucla for
for var in seq :
expression
family.py
fam = [1.73, 1.68, 1.71, 1.89]
for height in fam :
print(height)
# second iteration
# height = 1.68
1.73
1.68
Bucla for
for var in seq :
expression
family.py
fam = [1.73, 1.68, 1.71, 1.89]
for height in fam :
print(height)
1.73
1.68
1.71
1.89
- Fără acces la indecși
Bucla for
for var in seq :
expression
family.py
fam = [1.73, 1.68, 1.71, 1.89]
- ???
index 0: 1.73
index 1: 1.68
index 2: 1.71
index 3: 1.89
enumerate
for var in seq :
expression
family.py
fam = [1.73, 1.68, 1.71, 1.89]for index, height in enumerate(fam) : print("index " + str(index) + ": " + str(height))
index 0: 1.73
index 1: 1.68
index 2: 1.71
index 3: 1.89
Iterare peste șir de caractere
for var in seq :
expression
strloop.py
for c in "family" :
print(c.capitalize())
F
A
M
I
L
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Să exersăm!
Python intermediar
