SELECT में Subqueries

SQL में Data Manipulation

Mona Khalil

Data Scientist, Greenhouse Software

क्या SELECT करें?

एक single value लौटाती है
- व्यक्तिगत मानों से तुलना करने के लिए aggregate values शामिल करें

गणितीय गणनाओं में उपयोग
- औसत से विचलन

SELECT में Subqueries

सभी seasons में कुल matches निकालें

SELECT COUNT(id) FROM match;

SELECT में Subqueries

SELECT
  season,
  COUNT(id) AS matches,
  12837 as total_matches
FROM match
GROUP BY season;

| season    | matches | total_matches |
|-----------|---------|---------------|
| 2011/2012 | 3220    | 12837         |
| 2012/2013 | 3260    | 12837         |
| 2013/2014 | 3032    | 12837         |
| 2014/2015 | 3325    | 12837         |

SELECT में Subqueries

SELECT
  season,
  COUNT(id) AS matches,
  (SELECT COUNT(id) FROM match) as total_matches
FROM match
GROUP BY season;

| season    | matches | total_matches |
|-----------|---------|---------------|
| 2011/2012 | 3220    | 12837         |
| 2012/2013 | 3260    | 12837         |
| 2013/2014 | 3032    | 12837         |
| 2014/2015 | 3325    | 12837         |

गणितीय गणनाओं के लिए SELECT subqueries

SELECT AVG(home_goal + away_goal) 
FROM match
WHERE season = '2011/2012';

2.72

SELECT
  date,
  (home_goal + away_goal) AS goals,
  (home_goal + away_goal) - 2.72 AS diff
FROM match
WHERE season = '2011/2012';

SELECT में Subqueries

SELECT
  date,
  (home_goal + away_goal) AS goals,
  (home_goal + away_goal) - 
     (SELECT AVG(home_goal + away_goal) 
      FROM match
      WHERE season = '2011/2012') AS diff
FROM match
WHERE season = '2011/2012';

| date       | goals | diff              |
|------------|-------|-------------------|
| 2011-07-29 | 3     | 0.28354037267081  |
| 2011-07-30 | 2     | -0.71645962732919 |
| 2011-07-30 | 4     | 1.28354037267081  |
| 2011-07-30 | 1     | -1.71645962732919 |

SELECT subqueries — ध्यान रखने योग्य बातें

SINGLE value ही लौटनी चाहिए
- वरना error आएगा
सभी filters सही जगह पर हों
- main और subquery, दोनों को ठीक से filter करें!

SELECT
    date,
    (home_goal + away_goal) AS goals,
    (home_goal + away_goal) - 
       (SELECT AVG(home_goal + away_goal) 
        FROM match
        WHERE season = '2011/2012') AS diff
FROM match
WHERE season = '2011/2012';

अभ्यास करते हैं!

SQL में Data Manipulation