Oracle SQL 入门
Hadrien Lacroix
Content Developer
NULL 的算术表达式结果为 NULLNULL + 10 = NULLNULLCOUNT 不统计列中的 NULL 值真实数据并不完美。
不能用 = 判断 NULL
请改用:
IS NULL SELECT * FROM Customer WHERE LastName IS NULL
IS NOT NULLSELECT * FROM Customer WHERE LastName IS NOT NULL
NVL(x, y):将可能为 NULL 的 x 转为非空值 y。
SELECT NVL(HireDate, '11/19/2004')
FROM Employee
NULLIF(x, y):比较 x 与 y,返回:
x=y,返回 NULLxSELECT c.CustomerId, i.BillingCity, c.City, NULLIF(i.BillingCity, c.City)
FROM Invoice i, Customer c
| CustomerId | BillingCity | City | NULLIF |
|------------|-------------|-----------|--------|
| 48 | Oslo | Amsterdam | Oslo |
| 49 | Boston | Vienne | Boston |
| 59 | London | London | NULL |
COALESCE:返回列表中第一个非空值
SELECT CustomerId, COALESCE(phone, email, fax) AS ContactMethod
FROM Customer
| CustomerId | ContactMethod |
|------------|-------------------------|
| 59 | +91 080 22289999 |
| 58 | [email protected] |
| 57 | +56 (0)2 635 4444 |
Oracle SQL 入门