使用不同数据粒度进行聚合

提升 PostgreSQL 查询性能

Amy McCarty

Instructor

数据粒度:细节层级

 

  • 使行唯一
  • 1 个或多个列

 

Video_Games

id game first_yr
012 Grand Theft Auto 1997
234 Legend of Zelda 1986

 

 

 

Game_Platforms

game_id platform year
234 FCDS 1986
234 GameCube 2003
234 Wii 2006
提升 PostgreSQL 查询性能

连接不同粒度

Video_Games 表中《塞尔达传说》记录关联到 Games_Platforms 表中的全部 3 条记录。

SELECT g.id, g.game, g.first_yr
  , COUNT(p.platform) AS no_platforms
  , MAX(p.year) AS last_platform_yr
  , p.platform
FROM video_games g
INNER JOIN game_platforms p
  ON g.id = p.game_id
GROUP BY g.id, g.game, g.first_yr
, p.platform
提升 PostgreSQL 查询性能

连接不同粒度

 

输出

id game first_yr no_platforms last_platform_yr platform
234 Legend of Zelda 1986 3 2006 FCDS
234 Legend of Zelda 1986 3 2006 GameCube
234 Legend of Zelda 1986 3 2006 Wii
提升 PostgreSQL 查询性能

设置粒度变更

 

Game_Platforms

game_id platform year
234 FCDS 1986
234 GameCube 2003
234 Wii 2006

 

提升 PostgreSQL 查询性能

设置粒度变更

SELECT game_id, platform, year
  , COUNT(platform) AS no_platforms
  , MAX(year) AS last_platform_yr
FROM game_platforms
GROUP BY game_id, platform, year

输出

game_id platform year no_platforms last_platform_yr
234 FCDS 1986 3 2006
234 GameCube 2003 3 2006
234 Wii 2006 3 2006
提升 PostgreSQL 查询性能

重温 CTE

  • 独立查询,带临时结果集
  • WITH 语句
WITH cte AS
  ( SELECT * FROM tableA )

SELECT * FROM cte
  • 允许在连接前先聚合
提升 PostgreSQL 查询性能

CTE 来解围

WITH platforms_cte AS 
(  SELECT game_id, platform, year
      , COUNT(platform) AS no_platforms
      , MAX(year) AS last_platform_yr
   FROM game_platforms
   GROUP BY game_id, platform, year )
SELECT g.id, g.game, cte.no_platforms
  , cte.platform AS last_platform
FROM video_games g
INNER JOIN platforms_cte cte 
  ON g.id = cte.game_id
  AND cte.last_platform_yr = cte.year
提升 PostgreSQL 查询性能

CTE 来解围

WITH platforms_cte AS 
(  SELECT game_id, platform, year
      , COUNT(platform) AS no_platforms
      , MAX(year) AS last_platform_yr
   FROM game_platforms
   GROUP BY game_id, platform, year )
SELECT g.id, g.game, cte.no_platforms
  , cte.platform AS last_platform
FROM video_games g
INNER JOIN platforms_cte cte 
  ON g.id = cte.game_id
  AND cte.last_platform_yr = cte.year

输出

id game no_platforms last_platform
234 Legend of Zelda 3 Wii
提升 PostgreSQL 查询性能

连接时匹配数据粒度

 

  • 无重复或副本
  • 仅保留必要结果
  • 避免重复计数
提升 PostgreSQL 查询性能

¡Vamos a practicar!

提升 PostgreSQL 查询性能

Preparing Video For Download...