在 R 中处理日期和时间
Charlotte Wickham
Instructor
datetime_1 - datetime2:相减得到经过时间datetime_1 + (2 * timespan):加法与乘法生成过去/未来的新日期时间timespan1 / timespan2:相除进行单位换算releases <- read_csv("rversions.csv")
last_release <- filter(releases, date == max(date))
Sys.Date() - last_release$date
Time difference of 99 days
difftime(Sys.Date(), last_release$date)
Time difference of 99 days
time1 - time2 等同于 difftime(time1, time2)
units = "secs", "mins", "hours", "days", 或 "weeks"
difftime(Sys.Date(), last_release$date, units = "secs")
Time difference of 8553600 secs
difftime(Sys.Date(), last_release$date, units = "weeks")
Time difference of 14.14286 weeks
today()
"2017-10-07"
str(today())
Date[1:1], format: "2017-10-07"
now()
"2017-10-07 09:44:52 PDT"
str(now())
POSIXct[1:1], format: "2017-10-07 09:44:59"
在 R 中处理日期和时间