Python 供应链分析
Aaren Stubberfield
Supply Chain Analytics Mgr.
建模中的问题:
影子价格:
背景——玻璃公司资源规划:
| 资源 | 产A | 产B | 产C |
|---|---|---|---|
| 生产工时 | 6 | 5 | 8 |
| 仓库容量(平方英尺) | 10.5 | 20 | 10 |
| 利润(美元) | $500 | $450 | $600 |
约束:
# 初始化类、定义变量和目标
model = LpProblem("Max Glass Co. Profits",
LpMaximize)
A = LpVariable('A', lowBound=0)
B = LpVariable('B', lowBound=0)
C = LpVariable('C', lowBound=0)
model += 500 * A + 450 * B + 600 * C
# 约束 1
model += 6 * A + 5 * B + 8 * C <= 60
# 约束 2
model += 10.5 * A + 20 * B + 10 * C <= 150
# 约束 3
model += A <= 8
# 求解模型
model.solve()
print("Model Status:
{}".format(LpStatus[model.status]))
print("Objective = ", value(model.objective))
for v in model.variables():
print(v.name, "=", v.varValue)
解:
| 产品 | 产A | 产B | 产C |
|---|---|---|---|
| 生产件数 | 6.667 | 4 | 0 |
目标值为 $5133.33
决策变量:
约束:
Python 代码:
o = [{'name':name, 'shadow price':c.pi}
for name, c in model.constraints.items()]
print(pd.DataFrame(o))
输出:
name shadow price
_C1 78.148148
_C2 2.962963
_C3 -0.000000
回忆这些约束:
slack:
Python:
o = [{'name':name, 'shadow price':c.pi, 'slack': c.slack}
for name, c in model.constraints.items()]
print(pd.DataFrame(o))
输出:
name shadow price slack
_C1 78.148148 -0.000000
_C2 2.962963 -0.000000
_C3 -0.000000 1.333333
关于"绑定"的更多信息
slack = 0,则为"绑定"(binding)回忆这些约束:
shadow pricesslackslack = 0,则为绑定slack > 0,则为非绑定Python 供应链分析