Redshift 中的窗口函数

Redshift 入门

Jason Myers

Principal Architect

窗口函数

  • 在数据窗口(分区)上操作,为窗口内每行返回一个值
  • 分组函数会聚合结果行,窗口函数不会
  • 通过 OVER 子句定义

三个核心概念

  • 分区:形成行组(PARTITION BY
  • 排序:分区内顺序(ORDER BY
  • 框架:可选,对行施加额外限制
Redshift 入门

用窗口计算平均值

SELECT division_id,
       sale_date,
       revenue,

-- Calculate the average revenue AVG(revenue) OVER ( -- By division for each year and month PARTITION BY division_id, DATE_PART('year', sale_date) DATE_PART('month', sale_date), ) AS month_avg_revenue
FROM orders ORDER BY division_id, sale_date DESC;
Redshift 入门

用窗口计算平均值(续)

division_id | sale_date  | revenue | dept_month_avg_revenue
============|============|=========|=======================
      1     | 2024-01-23 | 350460 | 225500 
      1     | 2024-01-09 | 100540 | 225500 
      1     | 2023-12-15 | 231000 | 231000 
      1     | 2023-11-12 | 124000 | 68000 
      1     | 2023-11-07 | 75000  | 68000 
      1     | 2023-11-01 | 5000   | 68000 
      2     | 2024-01-10 | 500    | 500 
      2     | 2023-12-11 | 1000   | 16166.666666666667 
      2     | 2023-12-08 | 37000  | 16166.666666666667 
      2     | 2023-12-01 | 10500  | 16166.666666666667 
Redshift 入门

用 LAG 计算环比(月环比)

  • LAG 与 LEAD 按 ORDER BY 获取窗口内相邻上一行(之前)或下一行(之后)的数据
SELECT division_id,
       DATE_PART('year', sale_date) AS sales_year,
       DATE_PART('month', sale_date) AS sales_month,

-- Count records for the window COUNT(*) AS current_month_sales,
-- Count the previous windows records LAG(COUNT(*), 1) OVER (
-- For each division PARTITION BY division_id -- Ordered by year and month ORDER BY DATE_PART('year', sale_date), DATE_PART('month', sale_date) ) AS prior_month_sales
Redshift 入门

用 LAG 计算环比(月环比)(续)

  FROM sales_data
 -- Make sure to group by all the window clauses
 GROUP BY division_id, 
          sales_year, 
          sales_month
 ORDER BY division_id, 
          sales_year DESC, 
          sales_month DESC;
Redshift 入门

用 LAG 计算环比(月环比)结果

division_id sales_year sales_month current_month_sales prior_month_sales
1 2024 1 2 1
1 2023 12 1 3
1 2023 11 3 null
2 2024 1 1 3
2 2023 12 3 null
Redshift 入门

在窗口内对数据排名

  • RANKORDER BY 对窗口内值进行排名,从 1 开始
SELECT division_id,
       sale_date,
       revenue,
       -- Calculate the rank for each sale in the window
       RANK() OVER (
           -- For each division 
           PARTITION BY division_id 
               -- Using revenue for the rank
               ORDER BY revenue desc
       ) as division_sales_rank
  FROM sales_data
 -- Put them in rank order by division
 ORDER BY division_id, division_sales_rank;
Redshift 入门

在窗口内对数据排名(结果)

division_id sale_date revenue division_sales_rank
1 2024-01-23 350460 1
1 2023-12-15 231000 2
1 2023-11-12 124000 3
1 2024-01-09 100540 4
1 2023-11-07 75000 5
1 2023-11-01 5000 6
2 2023-12-08 37000 1
2 2023-12-01 10500 2
2 2023-12-11 1000 3
2 2024-01-10 500 4
Redshift 入门

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Redshift 入门

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