使用 purrr 的函数式编程进阶
Colin Fay
Data Scientist & R Hacker at ThinkR
possibly() 创建一个函数,该函数返回:
结果
otherwise 的值
library(purrr) possible_sum <- possibly(sum, otherwise = "nop") possible_sum(1)possible_sum("a")
0"nop"
possibly() 可返回:
ps <- possibly(sum, FALSE)
ps("a")
FALSE
NAps <- possibly(sum, NA)
ps("a")
NA
ps <- possibly(sum, "nope")
ps("a")
"nope"
ps <- possibly(sum, 0)
ps("a")
0
使用 purrr 的函数式编程进阶