Filtrarea rândurilor într-un data.table

Manipularea datelor cu data.table în R

Matt Dowle and Arun Srinivasan

Instructors, DataCamp

Sintaxa generală a unui data.table

Primul argument i este utilizat pentru subsetting sau filtrarea rândurilor

# General form of data.table syntax
DT[i, j, by]
   |  |  |
   |  |  --> grouped by what?
   |  -----> what to do?
   --------> on which rows?

Numere de rând

# Subset 3rd and 4th rows from batrips
batrips[3:4]

# Same as
batrips[3:4, ]

# Subset everything except first five rows
batrips[-(1:5)] 

# Same as
batrips[!(1:5)]

Simbolul special .N

.N este o valoare întreagă ce conține numărul de rânduri din data.table
Alternativă utilă la nrow(x) în i

nrow(batrips)

batrips[326339]

trip_id duration
588914      364

# Returns the last row
batrips[.N]

trip_id duration
588914      364

# Return all but the last 10 rows
ans <- batrips[1:(.N-10)] 
nrow(ans)

Expresii logice (I)

# Subset rows where subscription_type is "Subscriber"
batrips[subscription_type == "Subscriber"]

# If batrips was only a data frame
batrips[batrips$subscription_type == "Subscriber", ]

Expresii logice (II)

# Subset rows where start_terminal = 58 and end_terminal is not 65
batrips[start_terminal == 58 & end_terminal != 65]

# If batrips was only a data frame
batrips[batrips$start_terminal == 58 & batrips$end_terminal != 65]

Expresii logice (III)

Optimizat automat prin indici secundari pentru viteză

set.seed(1)
dt <- data.table(x = sample(10000, 10e6, TRUE), 
                 y = sample(letters, 1e6, TRUE))
indices(dt)

NULL

# 0.207s on first run 
#(time to create index + subset)
system.time(dt[x == 900])

user  system elapsed 
0.207   0.015   0.226

indices(dt)

"x"

# 0.002s on subsequent runs
#(instant subset using index)
system.time(dt[x == 900])

user  system elapsed 
0.002   0.000   0.002

Să exersăm!

Manipularea datelor cu data.table în R