Python 機率基礎
Alexander A. Ramírez M.
CEO @ Synergy Vision


$$P(Face\ card)=?$$

$$P(Face\ card)=\color{red}{P(Club\ and\ Face\ card)}+...$$

$$P(Face\ card)=P(Club\ and\ Face\ card)+\color{red}{P(Spade\ and\ Face\ card)}+...$$

$$P(Face\ card)=P(Club\ and\ Face\ card)+P(Spade\ and\ Face\ card)+$$ $$\color{red}{P(Heart\ and\ Face\ card)}+...$$

$$P(Face\ card)=P(Club\ and\ Face\ card)+P(Spade\ and\ Face\ card)+$$ $$P(Heart\ and\ Face\ card)+\color{red}{P(Diamond\ and\ Face\ card)}$$
全機率計算,程式中的 FC 指 Face card(人頭牌)
P_Club_n_FC = 3/52
P_Spade_n_FC = 3/52
P_Heart_n_FC = 3/52
P_Diamond_n_FC = 3/52
P_Face_card = P_Club_n_FC + P_Spade_n_FC + P_Heart_n_FC + P_Diamond_n_FC
print(P_Face_card)
人頭牌的機率為:
0.230769230769



$$P(D)=?$$

$$P(D)=\color{red}{P(V1\ and\ D)}+...$$

$$P(D)=P(V1\ and\ D)+\color{red}{P(V2\ and\ D)}+...$$

$$P(D)=P(V1\ and\ D)+P(V2\ and\ D)+\color{red}{P(V3\ and\ D)}$$

$$P(D)=P(V1)P(D|V1)+P(V2)P(D|V2)+P(V3)P(D|V3)$$
某款電子零件由 3 家供應商 V1、V2、V3 生產。
V1 產量佔一半,V2 與 V3 各佔 25%。在已知由 V1 生產下,瑕疵機率為 1%;V2 為 2%,V3 為 3%。
P_V1 = 0.5
P_V2 = 0.25
P_V3 = 0.25
P_D_g_V1 = 0.01
P_D_g_V2 = 0.02
P_D_g_V3 = 0.03
套用全機率公式
P_Damaged = P_V1 * P_D_g_V1 + P_V2 * P_D_g_V2 + P_V3 * P_D_g_V3
print(P_Damaged)
瑕疵的機率為:
0.0175
Python 機率基礎