在 R 中處理日期與時間
Charlotte Wickham
Instructor
datetime_1 - datetime2:相減以取得經過時間datetime_1 + (2 * timespan):加法與乘法可產生過去或未來的新日期時間timespan1 / timespan2:相除以轉換單位releases <- read_csv("rversions.csv")
last_release <- filter(releases, date == max(date))
Sys.Date() - last_release$date
Time difference of 99 days
difftime(Sys.Date(), last_release$date)
Time difference of 99 days
time1 - time2 與 difftime(time1, time2) 等價。
units = "secs"、"mins"、"hours"、"days" 或 "weeks"
difftime(Sys.Date(), last_release$date, units = "secs")
Time difference of 8553600 secs
difftime(Sys.Date(), last_release$date, units = "weeks")
Time difference of 14.14286 weeks
today()
"2017-10-07"
str(today())
Date[1:1], format: "2017-10-07"
now()
"2017-10-07 09:44:52 PDT"
str(now())
POSIXct[1:1], format: "2017-10-07 09:44:59"
在 R 中處理日期與時間